Postman Pat and his Triangle Collection

SydneyRoverP6B

SydneyRoverP6B

Well-Known Member
Staff member
Unbeknownst to most people, Postman Pat is actually an ardent collector of triangles, with his collection being the envy of all the people in Greendale. Pat's latest acquisition is a blue triangle which has an area of 96 square cm and a perimeter of 48cm. Pat knows this to be true as it says so on the box in which it came. Unfortunately, Pat does not have a ruler in which to make measurements, and sadly no one in all of Greendale has one either. So Pat needs to know.....what is the length of the hypotenuse? Pat knows the area and the perimeter, so can you please help Pat?

Ron.
 
vaultsman said:
:wink:

(It's 20 by the way!)

Cheers Ron,
Click to expand...

LMAO! In the picture x = 5cm!

Ironically enough, that picture DOES relate to the problem in hand.

The perimeter of the 3, 4, 5 triangle is 3 + 4 + 5 = 12cm

Pat's triangle has a perimeter of 48cm, which is 4 x 12cm.

So, if we 4 x the 3, 4, 5 triangle, we have 12, 16, 20. 12 + 16 + 20 = 48cm.

The area is xy/2, x = 12, y =16, xy/2 = 12 x 16 / 2 = 12 x 8 = 80 + 16 = 96cm^2

The hypotenuse is therefore 20cm!
 
darth sidious said:
vaultsman said:
:wink:

(It's 20 by the way!)

Cheers Ron,
Click to expand...

LMAO! In the picture x = 5cm!

Ironically enough, that picture DOES relate to the problem in hand.

The perimeter of the 3, 4, 5 triangle is 3 + 4 + 5 = 12cm

Pat's triangle has a perimeter of 48cm, which is 4 x 12cm.

So, if we 4 x the 3, 4, 5 triangle, we have 12, 16, 20. 12 + 16 + 20 = 48cm.

The area is xy/2, x = 12, y =16, xy/2 = 12 x 16 / 2 = 12 x 8 = 80 + 16 = 96cm^2

The hypotenuse is therefore 20cm!
Click to expand...

Yep...you got there! :wink:
 
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